修复es的should的问题

internal/logic/attr.go

@@ -55,8 +55,9 @@ func MatchGoodsNameByAttrs(bomItems []model.BomItem) (result []model.BomItem, er
 		if responses.Hits != nil {
 			for _, hit := range responses.Hits.Hits {
 				res, _ := hit.Source.MarshalJSON()
+				//还要去判断至少符合特定数量参数匹配的结果,比如最小匹配参数为2,那就是要有两个参数匹配到才正确
 				bomItems[key].GoodsName = gjson.Get(string(res), "goods_name").String()
-				fmt.Println(gjson.Get(string(res), "goods_name").String())
+				fmt.Println(string(res))
 			}
 		}
 	}
@@ -114,7 +115,6 @@ func changeKeyword(attr string) (result string) {
 		compile, _ := regexp.Compile(regexpStr)
 		attr = compile.ReplaceAllString(attr, regular)
 	}
-	fmt.Println(attr)
 	return attr
 }
 
@@ -198,21 +198,24 @@ func getAttrValueByAttr(attr string) (attrValue string) {
 
 //获取匹配的条件
 func getQuery(attrs []string) (query *es.BoolQuery) {
-	subQuery := es.NewBoolQuery()
+	var subQuery *es.TermQuery
+	query = es.NewBoolQuery()
 	for _, attr := range attrs {
+		//还要判断是不是一个单位对应多个属性的
 		if strings.Contains(attr, "|") {
 			name := strings.Split(attr, "€")[0]
 			value := strings.Split(attr, "€")[1]
 			multiAttr := strings.Split(name, "|")
 			for _, temp := range multiAttr {
-				subQuery = subQuery.Should(es.NewTermQuery("attrs.attr_value", temp+"€"+value))
+				subQuery = es.NewTermQuery("attrs.attr_value", temp+"€"+value)
 			}
 		} else {
-			subQuery = subQuery.Should(es.NewTermQuery("attrs.attr_value", attr))
+			subQuery = es.NewTermQuery("attrs.attr_value", attr)
 		}
+		nestedQuery := es.NewNestedQuery("attrs", subQuery)
+		query.Should(nestedQuery)
+		query.MinimumNumberShouldMatch(2)
 	}
-	nestedQuery := es.NewNestedQuery("attrs", subQuery)
-	query = es.NewBoolQuery()
-	query = query.Filter(nestedQuery)
+
 	return query
 }